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14343314121 = 325927011891
BaseRepresentation
bin11010101101110110…
…11001101011001001
31101000121110212000100
431112323121223021
5213333342022441
610331135000013
71015304105223
oct152673315311
941017425010
1014343314121
1160a0477214
122943669009
131477793b26
149a0d23413
1558e34acb6
hex356ed9ac9

14343314121 has 12 divisors (see below), whose sum is σ = 21069275760. Its totient is φ = 9400137720.

The previous prime is 14343314113. The next prime is 14343314129. The reversal of 14343314121 is 12141334341.

14343314121 is a `hidden beast` number, since 1 + 4 + 343 + 314 + 1 + 2 + 1 = 666.

It is an interprime number because it is at equal distance from previous prime (14343314113) and next prime (14343314129).

It is not a de Polignac number, because 14343314121 - 23 = 14343314113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14343314129) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13505415 + ... + 13506476.

It is an arithmetic number, because the mean of its divisors is an integer number (1755772980).

Almost surely, 214343314121 is an apocalyptic number.

It is an amenable number.

14343314121 is a deficient number, since it is larger than the sum of its proper divisors (6725961639).

14343314121 is a wasteful number, since it uses less digits than its factorization.

14343314121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27011956 (or 27011953 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 14343314121 its reverse (12141334341), we get a palindrome (26484648462).

The spelling of 14343314121 in words is "fourteen billion, three hundred forty-three million, three hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 3 9 59 177 531 27011891 81035673 243107019 1593701569 4781104707 14343314121