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14344224550113 = 36178383740711
BaseRepresentation
bin1101000010111100011001…
…1010001010110011100001
31212210021221200010220022010
43100233012122022303201
53340003432441100423
650301351253503133
73010223153634363
oct320570632126341
955707850126263
1014344224550113
114630395894a57
12173800b941aa9
138008681282b3
1437839ac64d33
1519d1d5dc2693
hexd0bc668ace1

14344224550113 has 8 divisors (see below), whose sum is σ = 19439167696576. Its totient is φ = 9406048885200.

The previous prime is 14344224550079. The next prime is 14344224550141. The reversal of 14344224550113 is 31105542244341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-14344224550113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14344224554113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39191870173 + ... + 39191870538.

It is an arithmetic number, because the mean of its divisors is an integer number (2429895962072).

Almost surely, 214344224550113 is an apocalyptic number.

It is an amenable number.

14344224550113 is a deficient number, since it is larger than the sum of its proper divisors (5094943146463).

14344224550113 is an equidigital number, since it uses as much as digits as its factorization.

14344224550113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78383740775.

The product of its (nonzero) digits is 230400, while the sum is 39.

Adding to 14344224550113 its reverse (31105542244341), we get a palindrome (45449766794454).

The spelling of 14344224550113 in words is "fourteen trillion, three hundred forty-four billion, two hundred twenty-four million, five hundred fifty thousand, one hundred thirteen".

Divisors: 1 3 61 183 78383740711 235151222133 4781408183371 14344224550113