14344440121 has 4 divisors (see below), whose sum is σ = 15648480144. Its totient is φ = 13040400100.

The previous prime is 14344440119. The next prime is 14344440139. The reversal of 14344440121 is 12104444341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14344440121 - 2¹ = 14344440119 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14344440121.

It is not an unprimeable number, because it can be changed into a prime (14344440101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 652019995 + ... + 652020016.

It is an arithmetic number, because the mean of its divisors is an integer number (3912120036).

Almost surely, 2^14344440121 is an apocalyptic number.

14344440121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14344440121 is a deficient number, since it is larger than the sum of its proper divisors (1304040023).

14344440121 is a wasteful number, since it uses less digits than its factorization.

14344440121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1304040022.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 14344440121 its reverse (12104444341), we get a palindrome (26448884462).

The spelling of 14344440121 in words is "fourteen billion, three hundred forty-four million, four hundred forty thousand, one hundred twenty-one".