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14344521324305 = 579264713719397
BaseRepresentation
bin1101000010111101100000…
…0110010001011100010001
31212210022201100120120221212
43100233120012101130101
53340010034424334210
650301440534425505
73010233416320304
oct320573006213421
955708640516855
1014344521324305
114630528365887
121738093202295
138008b4766a23
143783c8438b3b
1519d201e95805
hexd0bd8191711

14344521324305 has 16 divisors (see below), whose sum is σ = 17437903633920. Its totient is φ = 11326074806592.

The previous prime is 14344521324253. The next prime is 14344521324313. The reversal of 14344521324305 is 50342312544341.

It is a cyclic number.

It is not a de Polignac number, because 14344521324305 - 210 = 14344521323281 is a prime.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5814134 + ... + 7905263.

It is an arithmetic number, because the mean of its divisors is an integer number (1089868977120).

Almost surely, 214344521324305 is an apocalyptic number.

It is an amenable number.

14344521324305 is a deficient number, since it is larger than the sum of its proper divisors (3093382309615).

14344521324305 is a wasteful number, since it uses less digits than its factorization.

14344521324305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13722128.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 14344521324305 its reverse (50342312544341), we get a palindrome (64686833868646).

The spelling of 14344521324305 in words is "fourteen trillion, three hundred forty-four billion, five hundred twenty-one million, three hundred twenty-four thousand, three hundred five".

Divisors: 1 5 79 395 2647 13235 209113 1045565 13719397 68596985 1083832363 5419161815 36315243859 181576219295 2868904264861 14344521324305