Base | Representation |
---|---|
bin | 1000010110011000010… |
… | …1001010111001000011 |
3 | 111201021000222212110010 |
4 | 2011212011022321003 |
5 | 4322234304132011 |
6 | 145522021240003 |
7 | 13235511401151 |
oct | 2054605127103 |
9 | 451230885403 |
10 | 143446552131 |
11 | 55920925833 |
12 | 23973b63003 |
13 | 106b0936a5c |
14 | 6d2b2763d1 |
15 | 3ae85c21a6 |
hex | 216614ae43 |
143446552131 has 4 divisors (see below), whose sum is σ = 191262069512. Its totient is φ = 95631034752.
The previous prime is 143446552103. The next prime is 143446552141. The reversal of 143446552131 is 131255644341.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 143446552131 - 27 = 143446552003 is a prime.
It is a super-2 number, since 2×1434465521312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 143446552131.
It is not an unprimeable number, because it can be changed into a prime (143446552141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23907758686 + ... + 23907758691.
It is an arithmetic number, because the mean of its divisors is an integer number (47815517378).
Almost surely, 2143446552131 is an apocalyptic number.
143446552131 is a deficient number, since it is larger than the sum of its proper divisors (47815517381).
143446552131 is an equidigital number, since it uses as much as digits as its factorization.
143446552131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47815517380.
The product of its digits is 172800, while the sum is 39.
The spelling of 143446552131 in words is "one hundred forty-three billion, four hundred forty-six million, five hundred fifty-two thousand, one hundred thirty-one".
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