Base | Representation |
---|---|
bin | 11010101110101010… |
… | …00110001110011001 |
3 | 1101001002011002011210 |
4 | 31113111012032121 |
5 | 213342103101301 |
6 | 10331535213333 |
7 | 1015415262024 |
oct | 152725061631 |
9 | 41032132153 |
10 | 14350050201 |
11 | 60a4258123 |
12 | 2945977249 |
13 | 1478cb1b86 |
14 | 9a1b981bb |
15 | 58ec2bad6 |
hex | 357546399 |
14350050201 has 4 divisors (see below), whose sum is σ = 19133400272. Its totient is φ = 9566700132.
The previous prime is 14350050179. The next prime is 14350050203. The reversal of 14350050201 is 10205005341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10205005341 = 3 ⋅3401668447.
It is not a de Polignac number, because 14350050201 - 26 = 14350050137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14350050203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2391675031 + ... + 2391675036.
It is an arithmetic number, because the mean of its divisors is an integer number (4783350068).
Almost surely, 214350050201 is an apocalyptic number.
It is an amenable number.
14350050201 is a deficient number, since it is larger than the sum of its proper divisors (4783350071).
14350050201 is an equidigital number, since it uses as much as digits as its factorization.
14350050201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4783350070.
The product of its (nonzero) digits is 600, while the sum is 21.
Adding to 14350050201 its reverse (10205005341), we get a palindrome (24555055542).
The spelling of 14350050201 in words is "fourteen billion, three hundred fifty million, fifty thousand, two hundred one".
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