14353341011401 has 4 divisors (see below), whose sum is σ = 16403818298752. Its totient is φ = 12302863724052.

The previous prime is 14353341011371. The next prime is 14353341011417. The reversal of 14353341011401 is 10411014335341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14353341011401 - 2⁵ = 14353341011369 is a prime.

It is a super-2 number, since 2×14353341011401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14353341011491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025238643665 + ... + 1025238643678.

It is an arithmetic number, because the mean of its divisors is an integer number (4100954574688).

Almost surely, 2^{14353341011401} is an apocalyptic number.

It is an amenable number.

14353341011401 is a deficient number, since it is larger than the sum of its proper divisors (2050477287351).

14353341011401 is an equidigital number, since it uses as much as digits as its factorization.

14353341011401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2050477287350.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 14353341011401 its reverse (10411014335341), we get a palindrome (24764355346742).

The spelling of 14353341011401 in words is "fourteen trillion, three hundred fifty-three billion, three hundred forty-one million, eleven thousand, four hundred one".