Base | Representation |
---|---|
bin | 1000010110101101001… |
… | …0111010110000101001 |
3 | 111201111010121211012022 |
4 | 2011223102322300221 |
5 | 4322424203322103 |
6 | 145534424354225 |
7 | 13240623141125 |
oct | 2055322726051 |
9 | 451433554168 |
10 | 143534042153 |
11 | 55966252337 |
12 | 23999315975 |
13 | 106c5aba3b8 |
14 | 6d38b2c585 |
15 | 3b01105138 |
hex | 216b4bac29 |
143534042153 has 4 divisors (see below), whose sum is σ = 143757268368. Its totient is φ = 143310815940.
The previous prime is 143534042137. The next prime is 143534042189. The reversal of 143534042153 is 351240435341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 351240435341 = 81157 ⋅4327913.
It is a cyclic number.
It is not a de Polignac number, because 143534042153 - 24 = 143534042137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143534042053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111612143 + ... + 111613428.
It is an arithmetic number, because the mean of its divisors is an integer number (35939317092).
Almost surely, 2143534042153 is an apocalyptic number.
It is an amenable number.
143534042153 is a deficient number, since it is larger than the sum of its proper divisors (223226215).
143534042153 is an equidigital number, since it uses as much as digits as its factorization.
143534042153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223226214.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 143534042153 its reverse (351240435341), we get a palindrome (494774477494).
The spelling of 143534042153 in words is "one hundred forty-three billion, five hundred thirty-four million, forty-two thousand, one hundred fifty-three".
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