Base | Representation |
---|---|
bin | 1101000011100000111110… |
… | …0110110010110010111001 |
3 | 1212211020021220102000010220 |
4 | 3100320033212302302321 |
5 | 3340134034341443001 |
6 | 50310053415130253 |
7 | 3011021361251355 |
oct | 320701746626271 |
9 | 55736256360126 |
10 | 14354042531001 |
11 | 4634573888348 |
12 | 1739aab973989 |
13 | 8017711b5844 |
14 | 378a4cb66465 |
15 | 19d5accc8c36 |
hex | d0e0f9b2cb9 |
14354042531001 has 16 divisors (see below), whose sum is σ = 19278642190464. Its totient is φ = 9499403874944.
The previous prime is 14354042530973. The next prime is 14354042531009. The reversal of 14354042531001 is 10013524045341.
It is a cyclic number.
It is not a de Polignac number, because 14354042531001 - 217 = 14354042399929 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14354042531009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53261476 + ... + 53530298.
It is an arithmetic number, because the mean of its divisors is an integer number (1204915136904).
Almost surely, 214354042531001 is an apocalyptic number.
It is an amenable number.
14354042531001 is a deficient number, since it is larger than the sum of its proper divisors (4924599659463).
14354042531001 is a wasteful number, since it uses less digits than its factorization.
14354042531001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 398880.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 14354042531001 its reverse (10013524045341), we get a palindrome (24367566576342).
The spelling of 14354042531001 in words is "fourteen trillion, three hundred fifty-four billion, forty-two million, five hundred thirty-one thousand, one".
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