Base | Representation |
---|---|
bin | 1101000011100100101011… |
… | …0000111000011001101001 |
3 | 1212211022212001222020101111 |
4 | 3100321022300320121221 |
5 | 3340143102431444040 |
6 | 50310340111550321 |
7 | 3011055102334654 |
oct | 320711260703151 |
9 | 55738761866344 |
10 | 14355035031145 |
11 | 4634a330493a6 |
12 | 173a12822b3a1 |
13 | 80189b9c8133 |
14 | 378b048c089b |
15 | 19d619ec7dea |
hex | d0e4ac38669 |
14355035031145 has 16 divisors (see below), whose sum is σ = 17299254807360. Its totient is φ = 11435309820864.
The previous prime is 14355035031121. The next prime is 14355035031163. The reversal of 14355035031145 is 54113053055341.
It is a cyclic number.
It is not a de Polignac number, because 14355035031145 - 213 = 14355035022953 is a prime.
It is a super-2 number, since 2×143550350311452 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14355035031098 and 14355035031107.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4372035 + ... + 6915544.
It is an arithmetic number, because the mean of its divisors is an integer number (1081203425460).
Almost surely, 214355035031145 is an apocalyptic number.
It is an amenable number.
14355035031145 is a deficient number, since it is larger than the sum of its proper divisors (2944219776215).
14355035031145 is a wasteful number, since it uses less digits than its factorization.
14355035031145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11288664.
The product of its (nonzero) digits is 270000, while the sum is 40.
Adding to 14355035031145 its reverse (54113053055341), we get a palindrome (68468088086486).
The spelling of 14355035031145 in words is "fourteen trillion, three hundred fifty-five billion, thirty-five million, thirty-one thousand, one hundred forty-five".
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