14355150110131 has 4 divisors (see below), whose sum is σ = 14569406081992. Its totient is φ = 14140894138272.

The previous prime is 14355150110123. The next prime is 14355150110159. The reversal of 14355150110131 is 13101105155341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14355150110131 - 2³ = 14355150110123 is a prime.

It is a super-2 number, since 2×14355150110131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14355150110093 and 14355150110102.

It is not an unprimeable number, because it can be changed into a prime (14355150110731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107127985830 + ... + 107127985963.

It is an arithmetic number, because the mean of its divisors is an integer number (3642351520498).

Almost surely, 2^{14355150110131} is an apocalyptic number.

14355150110131 is a deficient number, since it is larger than the sum of its proper divisors (214255971861).

14355150110131 is an equidigital number, since it uses as much as digits as its factorization.

14355150110131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214255971860.

The product of its (nonzero) digits is 4500, while the sum is 31.

Adding to 14355150110131 its reverse (13101105155341), we get a palindrome (27456255265472).

The spelling of 14355150110131 in words is "fourteen trillion, three hundred fifty-five billion, one hundred fifty million, one hundred ten thousand, one hundred thirty-one".