Base | Representation |
---|---|
bin | 11010101111100111… |
… | …10011010010110001 |
3 | 1101001122022000012221 |
4 | 31113303303102301 |
5 | 213401133132441 |
6 | 10332423521041 |
7 | 1015543554202 |
oct | 152763632261 |
9 | 41048260187 |
10 | 14358099121 |
11 | 60a8855423 |
12 | 29485b9181 |
13 | 147a86c652 |
14 | 9a2c915a9 |
15 | 5907bb8d1 |
hex | 357cf34b1 |
14358099121 has 4 divisors (see below), whose sum is σ = 14746155892. Its totient is φ = 13970042352.
The previous prime is 14358099079. The next prime is 14358099127. The reversal of 14358099121 is 12199085341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12360992400 + 1997106721 = 111180^2 + 44689^2 .
It is a cyclic number.
It is not a de Polignac number, because 14358099121 - 211 = 14358097073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14358099127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194028330 + ... + 194028403.
It is an arithmetic number, because the mean of its divisors is an integer number (3686538973).
Almost surely, 214358099121 is an apocalyptic number.
It is an amenable number.
14358099121 is a deficient number, since it is larger than the sum of its proper divisors (388056771).
14358099121 is an equidigital number, since it uses as much as digits as its factorization.
14358099121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 388056770.
The product of its (nonzero) digits is 77760, while the sum is 43.
The spelling of 14358099121 in words is "fourteen billion, three hundred fifty-eight million, ninety-nine thousand, one hundred twenty-one".
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