Base | Representation |
---|---|
bin | 1101000100001000011011… |
… | …1111000111110110101011 |
3 | 1212212020122010122001101020 |
4 | 3101002012333013312223 |
5 | 3340322233121111021 |
6 | 50315004455423523 |
7 | 3011545024500216 |
oct | 321020677076653 |
9 | 55766563561336 |
10 | 14364635332011 |
11 | 463900a183548 |
12 | 173bb67384ba3 |
13 | 80276b94ac33 |
14 | 37937591a77d |
15 | 19d9ccc317c6 |
hex | d1086fc7dab |
14364635332011 has 4 divisors (see below), whose sum is σ = 19152847109352. Its totient is φ = 9576423554672.
The previous prime is 14364635332001. The next prime is 14364635332039. The reversal of 14364635332011 is 11023353646341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14364635332011 - 211 = 14364635329963 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14364635332001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2394105888666 + ... + 2394105888671.
It is an arithmetic number, because the mean of its divisors is an integer number (4788211777338).
Almost surely, 214364635332011 is an apocalyptic number.
14364635332011 is a deficient number, since it is larger than the sum of its proper divisors (4788211777341).
14364635332011 is an equidigital number, since it uses as much as digits as its factorization.
14364635332011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4788211777340.
The product of its (nonzero) digits is 466560, while the sum is 42.
Adding to 14364635332011 its reverse (11023353646341), we get a palindrome (25387988978352).
The spelling of 14364635332011 in words is "fourteen trillion, three hundred sixty-four billion, six hundred thirty-five million, three hundred thirty-two thousand, eleven".
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