Search a number
-
+
14365551401 = 19175212311
BaseRepresentation
bin11010110000100000…
…01110101100101001
31101002011022121211022
431120100032230221
5213410040121101
610333251342225
71015664113025
oct153020165451
941064277738
1014365551401
116101a85433
12294abb1975
13147c27b696
149a3c71385
1559128ea1b
hex35840eb29

14365551401 has 4 divisors (see below), whose sum is σ = 14440763904. Its totient is φ = 14290338900.

The previous prime is 14365551397. The next prime is 14365551427. The reversal of 14365551401 is 10415556341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10415556341 = 37927481679.

It is a cyclic number.

It is not a de Polignac number, because 14365551401 - 22 = 14365551397 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14365551451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37605965 + ... + 37606346.

It is an arithmetic number, because the mean of its divisors is an integer number (3610190976).

Almost surely, 214365551401 is an apocalyptic number.

It is an amenable number.

14365551401 is a deficient number, since it is larger than the sum of its proper divisors (75212503).

14365551401 is an equidigital number, since it uses as much as digits as its factorization.

14365551401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75212502.

The product of its (nonzero) digits is 36000, while the sum is 35.

The spelling of 14365551401 in words is "fourteen billion, three hundred sixty-five million, five hundred fifty-one thousand, four hundred one".

Divisors: 1 191 75212311 14365551401