143663502541121 has 4 divisors (see below), whose sum is σ = 145058293828032. Its totient is φ = 142268711254212.

The previous prime is 143663502541051. The next prime is 143663502541187. The reversal of 143663502541121 is 121145205366341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143663502541121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143663502541021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 697395643301 + ... + 697395643506.

It is an arithmetic number, because the mean of its divisors is an integer number (36264573457008).

Almost surely, 2^{143663502541121} is an apocalyptic number.

It is an amenable number.

143663502541121 is a deficient number, since it is larger than the sum of its proper divisors (1394791286911).

143663502541121 is a wasteful number, since it uses less digits than its factorization.

143663502541121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1394791286910.

The product of its (nonzero) digits is 518400, while the sum is 44.

The spelling of 143663502541121 in words is "one hundred forty-three trillion, six hundred sixty-three billion, five hundred two million, five hundred forty-one thousand, one hundred twenty-one".