14401323154401 has 4 divisors (see below), whose sum is σ = 19201764205872. Its totient is φ = 9600882102932.

The previous prime is 14401323154381. The next prime is 14401323154433. The reversal of 14401323154401 is 10445132310441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14401323154401 - 2¹¹ = 14401323152353 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14401323154451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2400220525731 + ... + 2400220525736.

It is an arithmetic number, because the mean of its divisors is an integer number (4800441051468).

Almost surely, 2^{14401323154401} is an apocalyptic number.

It is an amenable number.

14401323154401 is a deficient number, since it is larger than the sum of its proper divisors (4800441051471).

14401323154401 is an equidigital number, since it uses as much as digits as its factorization.

14401323154401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4800441051470.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 14401323154401 its reverse (10445132310441), we get a palindrome (24846455464842).

The spelling of 14401323154401 in words is "fourteen trillion, four hundred one billion, three hundred twenty-three million, one hundred fifty-four thousand, four hundred one".