Base | Representation |
---|---|
bin | 10100111101010010101… |
… | …110101110000001100011 |
3 | 12002200102011012011110002 |
4 | 110331102232232001203 |
5 | 142044013204214021 |
6 | 3021341503330215 |
7 | 206023356132143 |
oct | 24752256560143 |
9 | 5080364164402 |
10 | 1440202023011 |
11 | 5058715501a4 |
12 | 1b31548b096b |
13 | a5a6c7a147b |
14 | 4d9c5964923 |
15 | 276e275050b |
hex | 14f52bae063 |
1440202023011 has 4 divisors (see below), whose sum is σ = 1440238169952. Its totient is φ = 1440165876072.
The previous prime is 1440202022981. The next prime is 1440202023047. The reversal of 1440202023011 is 1103202020441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1440202023011 is a prime.
It is a super-2 number, since 2×14402020230112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1440202025011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18013640 + ... + 18093413.
It is an arithmetic number, because the mean of its divisors is an integer number (360059542488).
Almost surely, 21440202023011 is an apocalyptic number.
1440202023011 is a deficient number, since it is larger than the sum of its proper divisors (36146941).
1440202023011 is an equidigital number, since it uses as much as digits as its factorization.
1440202023011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36146940.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1440202023011 its reverse (1103202020441), we get a palindrome (2543404043452).
The spelling of 1440202023011 in words is "one trillion, four hundred forty billion, two hundred two million, twenty-three thousand, eleven".
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