Base | Representation |
---|---|
bin | 1101000110010101001100… |
… | …1000100101100100001001 |
3 | 1212222212011102100022112211 |
4 | 3101211103020211210021 |
5 | 3341432124021302213 |
6 | 50344214102305121 |
7 | 3014353252654525 |
oct | 321452310454411 |
9 | 55885142308484 |
10 | 14402420103433 |
11 | 465303975056a |
12 | 17473514281a1 |
13 | 8061b0a9944b |
14 | 37b11bc04d85 |
15 | 19e98eede53d |
hex | d1953225909 |
14402420103433 has 16 divisors (see below), whose sum is σ = 15202773100800. Its totient is φ = 13606330026240.
The previous prime is 14402420103317. The next prime is 14402420103473. The reversal of 14402420103433 is 33430102420441.
It is not a de Polignac number, because 14402420103433 - 29 = 14402420102921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14402420103395 and 14402420103404.
It is not an unprimeable number, because it can be changed into a prime (14402420103473) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17021335 + ... + 17847427.
It is an arithmetic number, because the mean of its divisors is an integer number (950173318800).
Almost surely, 214402420103433 is an apocalyptic number.
It is an amenable number.
14402420103433 is a deficient number, since it is larger than the sum of its proper divisors (800352997367).
14402420103433 is a wasteful number, since it uses less digits than its factorization.
14402420103433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 828672.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14402420103433 its reverse (33430102420441), we get a palindrome (47832522523874).
The spelling of 14402420103433 in words is "fourteen trillion, four hundred two billion, four hundred twenty million, one hundred three thousand, four hundred thirty-three".
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