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14402925433 = 131958311439
BaseRepresentation
bin11010110100111101…
…10011001101111001
31101011202122102100201
431122132303031321
5213444122103213
610341104402201
71016626563151
oct153236631571
941152572321
1014402925433
116121092066
12295b616361
131486c35bb0
149a8bdd761
155946c36dd
hex35a7b3379

14402925433 has 8 divisors (see below), whose sum is σ = 16327203200. Its totient is φ = 12595270608.

The previous prime is 14402925431. The next prime is 14402925443. The reversal of 14402925433 is 33452920441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14402925433 - 21 = 14402925431 is a prime.

It is a super-2 number, since 2×144029254332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14402925392 and 14402925401.

It is not an unprimeable number, because it can be changed into a prime (14402925431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29155473 + ... + 29155966.

It is an arithmetic number, because the mean of its divisors is an integer number (2040900400).

Almost surely, 214402925433 is an apocalyptic number.

14402925433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

14402925433 is a deficient number, since it is larger than the sum of its proper divisors (1924277767).

14402925433 is a wasteful number, since it uses less digits than its factorization.

14402925433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58311471.

The product of its (nonzero) digits is 103680, while the sum is 37.

The spelling of 14402925433 in words is "fourteen billion, four hundred two million, nine hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 13 19 247 58311439 758048707 1107917341 14402925433