144033111041 has 4 divisors (see below), whose sum is σ = 144038934084. Its totient is φ = 144027288000.

The previous prime is 144033111017. The next prime is 144033111077. The reversal of 144033111041 is 140111330441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 140111330441 = 75029 ⋅1867429.

It can be written as a sum of positive squares in 2 ways, for example, as 22229319025 + 121803792016 = 149095^2 + 349004^2 .

It is a cyclic number.

It is not a de Polignac number, because 144033111041 - 2¹⁰ = 144033110017 is a prime.

It is a super-2 number, since 2×144033111041² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144033110998 and 144033111016.

It is not an unprimeable number, because it can be changed into a prime (144033101041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2874260 + ... + 2923941.

It is an arithmetic number, because the mean of its divisors is an integer number (36009733521).

Almost surely, 2^144033111041 is an apocalyptic number.

It is an amenable number.

144033111041 is a deficient number, since it is larger than the sum of its proper divisors (5823043).

144033111041 is an equidigital number, since it uses as much as digits as its factorization.

144033111041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5823042.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 144033111041 its reverse (140111330441), we get a palindrome (284144441482).

The spelling of 144033111041 in words is "one hundred forty-four billion, thirty-three million, one hundred eleven thousand, forty-one".