144034022413001 has 4 divisors (see below), whose sum is σ = 164610311329152. Its totient is φ = 123457733496852.

The previous prime is 144034022412983. The next prime is 144034022413063. The reversal of 144034022413001 is 100314220430441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144034022413001 - 2¹⁴ = 144034022396617 is a prime.

It is a super-2 number, since 2×144034022413001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144034022413081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10288144458065 + ... + 10288144458078.

It is an arithmetic number, because the mean of its divisors is an integer number (41152577832288).

Almost surely, 2^{144034022413001} is an apocalyptic number.

It is an amenable number.

144034022413001 is a deficient number, since it is larger than the sum of its proper divisors (20576288916151).

144034022413001 is an equidigital number, since it uses as much as digits as its factorization.

144034022413001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20576288916150.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 144034022413001 its reverse (100314220430441), we get a palindrome (244348242843442).

The spelling of 144034022413001 in words is "one hundred forty-four trillion, thirty-four billion, twenty-two million, four hundred thirteen thousand, one".