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144110113 = 720587159
BaseRepresentation
bin10001001011011…
…11001000100001
3101001011112220121
420211233020201
5243343010423
622144440241
73366626050
oct1045571041
9331145817
10144110113
117438a074
1240319081
1323b19074
14151d4397
15c9b945d
hex896f221

144110113 has 4 divisors (see below), whose sum is σ = 164697280. Its totient is φ = 123522948.

The previous prime is 144110089. The next prime is 144110119. The reversal of 144110113 is 311011441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311011441 = 1323923957.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144110113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144110119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10293573 + ... + 10293586.

It is an arithmetic number, because the mean of its divisors is an integer number (41174320).

Almost surely, 2144110113 is an apocalyptic number.

It is an amenable number.

144110113 is a deficient number, since it is larger than the sum of its proper divisors (20587167).

144110113 is an equidigital number, since it uses as much as digits as its factorization.

144110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20587166.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 144110113 is about 12004.5871649133. The cubic root of 144110113 is about 524.2818455883.

Adding to 144110113 its reverse (311011441), we get a palindrome (455121554).

The spelling of 144110113 in words is "one hundred forty-four million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 7 20587159 144110113