144112310313403 has 4 divisors (see below), whose sum is σ = 149081700324240. Its totient is φ = 139142920302568.

The previous prime is 144112310313371. The next prime is 144112310313421. The reversal of 144112310313403 is 304313013211441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144112310313403 - 2⁵ = 144112310313371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144112310317403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2484695005375 + ... + 2484695005432.

It is an arithmetic number, because the mean of its divisors is an integer number (37270425081060).

Almost surely, 2^{144112310313403} is an apocalyptic number.

144112310313403 is a deficient number, since it is larger than the sum of its proper divisors (4969390010837).

144112310313403 is an equidigital number, since it uses as much as digits as its factorization.

144112310313403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4969390010836.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 144112310313403 its reverse (304313013211441), we get a palindrome (448425323524844).

The spelling of 144112310313403 in words is "one hundred forty-four trillion, one hundred twelve billion, three hundred ten million, three hundred thirteen thousand, four hundred three".