1441131041323 has 4 divisors (see below), whose sum is σ = 1441204554280. Its totient is φ = 1441057528368.

The previous prime is 1441131041291. The next prime is 1441131041347. The reversal of 1441131041323 is 3231401311441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1441131041323 - 2⁵ = 1441131041291 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1441131041291 and 1441131041300.

It is not an unprimeable number, because it can be changed into a prime (1441131041353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36727065 + ... + 36766282.

It is an arithmetic number, because the mean of its divisors is an integer number (360301138570).

Almost surely, 2^{1441131041323} is an apocalyptic number.

1441131041323 is a deficient number, since it is larger than the sum of its proper divisors (73512957).

1441131041323 is an equidigital number, since it uses as much as digits as its factorization.

1441131041323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73512956.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1441131041323 its reverse (3231401311441), we get a palindrome (4672532352764).

The spelling of 1441131041323 in words is "one trillion, four hundred forty-one billion, one hundred thirty-one million, forty-one thousand, three hundred twenty-three".