Base | Representation |
---|---|
bin | 1000011000110111001… |
… | …1111100010001010001 |
3 | 111202222111021020202011 |
4 | 2012031303330101101 |
5 | 4330120424440213 |
6 | 150112112222521 |
7 | 13261154226505 |
oct | 2061563742121 |
9 | 452874236664 |
10 | 144113124433 |
11 | 56133113433 |
12 | 23b1b23aa41 |
13 | 10788a70c35 |
14 | 6d919cc305 |
15 | 3b36d9003d |
hex | 218dcfc451 |
144113124433 has 16 divisors (see below), whose sum is σ = 148762404864. Its totient is φ = 139504412160.
The previous prime is 144113124409. The next prime is 144113124443. The reversal of 144113124433 is 334421311441.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144113124433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 144113124395 and 144113124404.
It is not an unprimeable number, because it can be changed into a prime (144113124443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14248048 + ... + 14258158.
It is an arithmetic number, because the mean of its divisors is an integer number (9297650304).
Almost surely, 2144113124433 is an apocalyptic number.
It is an amenable number.
144113124433 is a deficient number, since it is larger than the sum of its proper divisors (4649280431).
144113124433 is a wasteful number, since it uses less digits than its factorization.
144113124433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12072.
The product of its digits is 13824, while the sum is 31.
Adding to 144113124433 its reverse (334421311441), we get a palindrome (478534435874).
The spelling of 144113124433 in words is "one hundred forty-four billion, one hundred thirteen million, one hundred twenty-four thousand, four hundred thirty-three".
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