14411330450131 has 4 divisors (see below), whose sum is σ = 14411338565832. Its totient is φ = 14411322334432.

The previous prime is 14411330450107. The next prime is 14411330450161. The reversal of 14411330450131 is 13105403311441.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 14411330450131 - 2¹⁹ = 14411329925843 is a prime.

It is a super-2 number, since 2×14411330450131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14411330450093 and 14411330450102.

It is not an unprimeable number, because it can be changed into a prime (14411330450161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121270 + ... + 5370043.

It is an arithmetic number, because the mean of its divisors is an integer number (3602834641458).

Almost surely, 2^{14411330450131} is an apocalyptic number.

14411330450131 is a deficient number, since it is larger than the sum of its proper divisors (8115701).

14411330450131 is an equidigital number, since it uses as much as digits as its factorization.

14411330450131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8115700.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 14411330450131 its reverse (13105403311441), we get a palindrome (27516733761572).

The spelling of 14411330450131 in words is "fourteen trillion, four hundred eleven billion, three hundred thirty million, four hundred fifty thousand, one hundred thirty-one".