144124321110131 has 4 divisors (see below), whose sum is σ = 144871079250792. Its totient is φ = 143377562969472.

The previous prime is 144124321110071. The next prime is 144124321110149. The reversal of 144124321110131 is 131011123421441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144124321110131 - 2²² = 144124316915827 is a prime.

It is a super-3 number, since 3×144124321110131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144124321110094 and 144124321110103.

It is not an unprimeable number, because it can be changed into a prime (144124321140131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373379070041 + ... + 373379070426.

It is an arithmetic number, because the mean of its divisors is an integer number (36217769812698).

Almost surely, 2^{144124321110131} is an apocalyptic number.

144124321110131 is a deficient number, since it is larger than the sum of its proper divisors (746758140661).

144124321110131 is an equidigital number, since it uses as much as digits as its factorization.

144124321110131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 746758140660.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 144124321110131 its reverse (131011123421441), we get a palindrome (275135444531572).

The spelling of 144124321110131 in words is "one hundred forty-four trillion, one hundred twenty-four billion, three hundred twenty-one million, one hundred ten thousand, one hundred thirty-one".