14412501104401 has 4 divisors (see below), whose sum is σ = 14412531603492. Its totient is φ = 14412470605312.

The previous prime is 14412501104333. The next prime is 14412501104411. The reversal of 14412501104401 is 10440110521441.

It is a Cunningham number, because it is equal to 3796380²+1.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7973417228176 + 6439083876225 = 2823724^2 + 2537535^2 .

It is a cyclic number.

It is not a de Polignac number, because 14412501104401 - 2⁷ = 14412501104273 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14412501104401.

It is not an unprimeable number, because it can be changed into a prime (14412501104411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14529376 + ... + 15489601.

It is an arithmetic number, because the mean of its divisors is an integer number (3603132900873).

Almost surely, 2^{14412501104401} is an apocalyptic number.

It is an amenable number.

14412501104401 is a deficient number, since it is larger than the sum of its proper divisors (30499091).

14412501104401 is an equidigital number, since it uses as much as digits as its factorization.

14412501104401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30499090.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 14412501104401 its reverse (10440110521441), we get a palindrome (24852611625842).

The spelling of 14412501104401 in words is "fourteen trillion, four hundred twelve billion, five hundred one million, one hundred four thousand, four hundred one".