14413340112131 has 4 divisors (see below), whose sum is σ = 15040007073552. Its totient is φ = 13786673150712.

The previous prime is 14413340112053. The next prime is 14413340112163. The reversal of 14413340112131 is 13121104331441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14413340112131 is a prime.

It is a super-2 number, since 2×14413340112131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14413340112094 and 14413340112103.

It is not an unprimeable number, because it can be changed into a prime (14413340112191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313333480676 + ... + 313333480721.

It is an arithmetic number, because the mean of its divisors is an integer number (3760001768388).

Almost surely, 2^{14413340112131} is an apocalyptic number.

14413340112131 is a deficient number, since it is larger than the sum of its proper divisors (626666961421).

14413340112131 is an equidigital number, since it uses as much as digits as its factorization.

14413340112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 626666961420.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 14413340112131 its reverse (13121104331441), we get a palindrome (27534444443572).

The spelling of 14413340112131 in words is "fourteen trillion, four hundred thirteen billion, three hundred forty million, one hundred twelve thousand, one hundred thirty-one".