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144138034003 = 251535730451
BaseRepresentation
bin1000011000111101001…
…0111101101101010011
3111210001020010210020211
42012033102331231103
54330143314042003
6150114402144551
713261606034245
oct2061722755523
9453036123224
10144138034003
1156146187357
1223b27652157
1310790c82c22
146d95034095
153b3916096d
hex218f4bdb53

144138034003 has 4 divisors (see below), whose sum is σ = 144143789608. Its totient is φ = 144132278400.

The previous prime is 144138033973. The next prime is 144138034049. The reversal of 144138034003 is 300430831441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300430831441 = 1323110063957.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144138034003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144138034303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2840073 + ... + 2890378.

It is an arithmetic number, because the mean of its divisors is an integer number (36035947402).

Almost surely, 2144138034003 is an apocalyptic number.

144138034003 is a deficient number, since it is larger than the sum of its proper divisors (5755605).

144138034003 is an equidigital number, since it uses as much as digits as its factorization.

144138034003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5755604.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 144138034003 its reverse (300430831441), we get a palindrome (444568865444).

The spelling of 144138034003 in words is "one hundred forty-four billion, one hundred thirty-eight million, thirty-four thousand, three".

Divisors: 1 25153 5730451 144138034003