Base | Representation |
---|---|
bin | 11010110110011001… |
… | …11010011000111011 |
3 | 1101012121101112222111 |
4 | 31123030322120323 |
5 | 214010220412220 |
6 | 10342215433151 |
7 | 1020134410144 |
oct | 153314723073 |
9 | 41177345874 |
10 | 14415013435 |
11 | 6127998a49 |
12 | 29636857b7 |
13 | 14895a8c64 |
14 | 9aa668acb |
15 | 5957b015a |
hex | 35b33a63b |
14415013435 has 4 divisors (see below), whose sum is σ = 17298016128. Its totient is φ = 11532010744.
The previous prime is 14415013381. The next prime is 14415013523. The reversal of 14415013435 is 53431051441.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53431051441 = 2441 ⋅21889001.
It is a cyclic number.
It is not a de Polignac number, because 14415013435 - 29 = 14415012923 is a prime.
It is a super-2 number, since 2×144150134352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14415013397 and 14415013406.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1441501339 + ... + 1441501348.
It is an arithmetic number, because the mean of its divisors is an integer number (4324504032).
Almost surely, 214415013435 is an apocalyptic number.
14415013435 is a deficient number, since it is larger than the sum of its proper divisors (2883002693).
14415013435 is an equidigital number, since it uses as much as digits as its factorization.
14415013435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2883002692.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14415013435 its reverse (53431051441), we get a palindrome (67846064876).
The spelling of 14415013435 in words is "fourteen billion, four hundred fifteen million, thirteen thousand, four hundred thirty-five".
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