144153412041001 has 4 divisors (see below), whose sum is σ = 157258267681104. Its totient is φ = 131048556400900.

The previous prime is 144153412040977. The next prime is 144153412041007. The reversal of 144153412041001 is 100140214351441.

144153412041001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144153412041001 - 2³¹ = 144151264557353 is a prime.

It is a super-2 number, since 2×144153412041001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144153412041007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6552427820035 + ... + 6552427820056.

It is an arithmetic number, because the mean of its divisors is an integer number (39314566920276).

Almost surely, 2^{144153412041001} is an apocalyptic number.

144153412041001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

144153412041001 is a deficient number, since it is larger than the sum of its proper divisors (13104855640103).

144153412041001 is a wasteful number, since it uses less digits than its factorization.

144153412041001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13104855640102.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 144153412041001 its reverse (100140214351441), we get a palindrome (244293626392442).

The spelling of 144153412041001 in words is "one hundred forty-four trillion, one hundred fifty-three billion, four hundred twelve million, forty-one thousand, one".