Base | Representation |
---|---|
bin | 10100111111000101110… |
… | …101111101110010110011 |
3 | 12002212101202020022210020 |
4 | 110333011311331302303 |
5 | 142111442111134301 |
6 | 3022301253334523 |
7 | 206122256546352 |
oct | 24770565756263 |
9 | 5085352208706 |
10 | 1442133302451 |
11 | 506672720006 |
12 | 1b35b3637443 |
13 | a5cb993747a |
14 | 4db2a251999 |
15 | 277a708b436 |
hex | 14fc5d7dcb3 |
1442133302451 has 4 divisors (see below), whose sum is σ = 1922844403272. Its totient is φ = 961422201632.
The previous prime is 1442133302429. The next prime is 1442133302453. The reversal of 1442133302451 is 1542033312441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1442133302451 - 221 = 1442131205299 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1442133302453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240355550406 + ... + 240355550411.
It is an arithmetic number, because the mean of its divisors is an integer number (480711100818).
Almost surely, 21442133302451 is an apocalyptic number.
1442133302451 is a deficient number, since it is larger than the sum of its proper divisors (480711100821).
1442133302451 is an equidigital number, since it uses as much as digits as its factorization.
1442133302451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 480711100820.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 1442133302451 its reverse (1542033312441), we get a palindrome (2984166614892).
The spelling of 1442133302451 in words is "one trillion, four hundred forty-two billion, one hundred thirty-three million, three hundred two thousand, four hundred fifty-one".
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