Search a number
-
+
14422021121 = 21168350811
BaseRepresentation
bin11010110111001111…
…01001010000000001
31101020002120120201102
431123213221100001
5214014014133441
610343025544145
71020251104544
oct153347512001
941202516642
1014422021121
116130944a22
122965aa5055
13148ab90811
149ab57085b
155961e669b
hex35b9e9401

14422021121 has 4 divisors (see below), whose sum is σ = 14490372144. Its totient is φ = 14353670100.

The previous prime is 14422021069. The next prime is 14422021127. The reversal of 14422021121 is 12112022441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14422021121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14422021093 and 14422021102.

It is not an unprimeable number, because it can be changed into a prime (14422021127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34175195 + ... + 34175616.

It is an arithmetic number, because the mean of its divisors is an integer number (3622593036).

Almost surely, 214422021121 is an apocalyptic number.

It is an amenable number.

14422021121 is a deficient number, since it is larger than the sum of its proper divisors (68351023).

14422021121 is an equidigital number, since it uses as much as digits as its factorization.

14422021121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68351022.

The product of its (nonzero) digits is 256, while the sum is 20.

Adding to 14422021121 its reverse (12112022441), we get a palindrome (26534043562).

The spelling of 14422021121 in words is "fourteen billion, four hundred twenty-two million, twenty-one thousand, one hundred twenty-one".

Divisors: 1 211 68350811 14422021121