Base | Representation |
---|---|
bin | 1101001000000000110111… |
… | …1001010011101000101011 |
3 | 1220002121202201200211112111 |
4 | 3102000031321103220223 |
5 | 3342420322222203003 |
6 | 50405354113023151 |
7 | 3016425433405654 |
oct | 322001571235053 |
9 | 56077681624474 |
10 | 14431323241003 |
11 | 4664320822619 |
12 | 1750a78b54ab7 |
13 | 808b38b3ba06 |
14 | 37c6a06ca52b |
15 | 1a05d26a1e6d |
hex | d200de53a2b |
14431323241003 has 4 divisors (see below), whose sum is σ = 14783306734728. Its totient is φ = 14079339747280.
The previous prime is 14431323241001. The next prime is 14431323241103. The reversal of 14431323241003 is 30014232313441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14431323241003 - 21 = 14431323241001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14431323241001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175991746801 + ... + 175991746882.
It is an arithmetic number, because the mean of its divisors is an integer number (3695826683682).
Almost surely, 214431323241003 is an apocalyptic number.
14431323241003 is a deficient number, since it is larger than the sum of its proper divisors (351983493725).
14431323241003 is an equidigital number, since it uses as much as digits as its factorization.
14431323241003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 351983493724.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 14431323241003 its reverse (30014232313441), we get a palindrome (44445555554444).
The spelling of 14431323241003 in words is "fourteen trillion, four hundred thirty-one billion, three hundred twenty-three million, two hundred forty-one thousand, three".
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