Base | Representation |
---|---|
bin | 1000011001101000100… |
… | …1100101100110000011 |
3 | 111210111220202222120111 |
4 | 2012122021211212003 |
5 | 4331031423002230 |
6 | 150144425052151 |
7 | 13266246552562 |
oct | 2063211454603 |
9 | 453456688514 |
10 | 144320125315 |
11 | 56229a48243 |
12 | 23b78627057 |
13 | 107bc909972 |
14 | 6db12b3bd9 |
15 | 3b4a12d92a |
hex | 219a265983 |
144320125315 has 4 divisors (see below), whose sum is σ = 173184150384. Its totient is φ = 115456100248.
The previous prime is 144320125259. The next prime is 144320125333. The reversal of 144320125315 is 513521023441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144320125315 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14432012527 + ... + 14432012536.
It is an arithmetic number, because the mean of its divisors is an integer number (43296037596).
Almost surely, 2144320125315 is an apocalyptic number.
144320125315 is a deficient number, since it is larger than the sum of its proper divisors (28864025069).
144320125315 is an equidigital number, since it uses as much as digits as its factorization.
144320125315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28864025068.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 144320125315 its reverse (513521023441), we get a palindrome (657841148756).
The spelling of 144320125315 in words is "one hundred forty-four billion, three hundred twenty million, one hundred twenty-five thousand, three hundred fifteen".
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