Base | Representation |
---|---|
bin | 1000011001101001100… |
… | …0100100111111011011 |
3 | 111210112012011122002111 |
4 | 2012122120210333123 |
5 | 4331033424230003 |
6 | 150145045213151 |
7 | 13266325140442 |
oct | 2063230447733 |
9 | 453465148074 |
10 | 144324055003 |
11 | 56231191717 |
12 | 23b79a011b7 |
13 | 107c068451b |
14 | 6db1a17d59 |
15 | 3b4a657e6d |
hex | 219a624fdb |
144324055003 has 4 divisors (see below), whose sum is σ = 144324962128. Its totient is φ = 144323147880.
The previous prime is 144324054997. The next prime is 144324055009. The reversal of 144324055003 is 300550423441.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is an interprime number because it is at equal distance from previous prime (144324054997) and next prime (144324055009).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144324055003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (144324055009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144888 + ... + 556453.
It is an arithmetic number, because the mean of its divisors is an integer number (36081240532).
Almost surely, 2144324055003 is an apocalyptic number.
144324055003 is a deficient number, since it is larger than the sum of its proper divisors (907125).
144324055003 is an equidigital number, since it uses as much as digits as its factorization.
144324055003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 907124.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 144324055003 its reverse (300550423441), we get a palindrome (444874478444).
The spelling of 144324055003 in words is "one hundred forty-four billion, three hundred twenty-four million, fifty-five thousand, three".
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