144330421141131 has 4 divisors (see below), whose sum is σ = 192440561521512. Its totient is φ = 96220280760752.

The previous prime is 144330421141057. The next prime is 144330421141171. The reversal of 144330421141131 is 131141124033441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144330421141131 - 2¹³ = 144330421132939 is a prime.

It is a super-2 number, since 2×144330421141131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144330421141092 and 144330421141101.

It is not an unprimeable number, because it can be changed into a prime (144330421141171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24055070190186 + ... + 24055070190191.

It is an arithmetic number, because the mean of its divisors is an integer number (48110140380378).

Almost surely, 2^{144330421141131} is an apocalyptic number.

144330421141131 is a deficient number, since it is larger than the sum of its proper divisors (48110140380381).

144330421141131 is an equidigital number, since it uses as much as digits as its factorization.

144330421141131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48110140380380.

The product of its (nonzero) digits is 13824, while the sum is 33.

Adding to 144330421141131 its reverse (131141124033441), we get a palindrome (275471545174572).

The spelling of 144330421141131 in words is "one hundred forty-four trillion, three hundred thirty billion, four hundred twenty-one million, one hundred forty-one thousand, one hundred thirty-one".