144331044424113 has 8 divisors (see below), whose sum is σ = 193553770557888. Its totient is φ = 95664507286544.

The previous prime is 144331044424111. The next prime is 144331044424183. The reversal of 144331044424113 is 311424440133441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 144331044424113 - 2¹ = 144331044424111 is a prime.

It is a super-3 number, since 3×144331044424113³ (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (144331044424111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 139047248445 + ... + 139047249482.

It is an arithmetic number, because the mean of its divisors is an integer number (24194221319736).

Almost surely, 2^{144331044424113} is an apocalyptic number.

It is an amenable number.

144331044424113 is a deficient number, since it is larger than the sum of its proper divisors (49222726133775).

144331044424113 is a wasteful number, since it uses less digits than its factorization.

144331044424113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278094498103.

The product of its (nonzero) digits is 221184, while the sum is 39.

Adding to 144331044424113 its reverse (311424440133441), we get a palindrome (455755484557554).

The spelling of 144331044424113 in words is "one hundred forty-four trillion, three hundred thirty-one billion, forty-four million, four hundred twenty-four thousand, one hundred thirteen".