Base | Representation |
---|---|
bin | 1000011001101011011… |
… | …1010101111111000001 |
3 | 111210112202100101012010 |
4 | 2012122313111333001 |
5 | 4331043010320001 |
6 | 150145534123133 |
7 | 13266453530526 |
oct | 2063267257701 |
9 | 453482311163 |
10 | 144332120001 |
11 | 562357a0003 |
12 | 23b806504a9 |
13 | 107c2249404 |
14 | 6db2b1714d |
15 | 3b4b1ec8d6 |
hex | 219add5fc1 |
144332120001 has 4 divisors (see below), whose sum is σ = 192442826672. Its totient is φ = 96221413332.
The previous prime is 144332119993. The next prime is 144332120029. The reversal of 144332120001 is 100021233441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 144332120001 - 23 = 144332119993 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 144332120001.
It is not an unprimeable number, because it can be changed into a prime (144332120081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24055353331 + ... + 24055353336.
It is an arithmetic number, because the mean of its divisors is an integer number (48110706668).
Almost surely, 2144332120001 is an apocalyptic number.
It is an amenable number.
144332120001 is a deficient number, since it is larger than the sum of its proper divisors (48110706671).
144332120001 is an equidigital number, since it uses as much as digits as its factorization.
144332120001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48110706670.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 144332120001 its reverse (100021233441), we get a palindrome (244353353442).
The spelling of 144332120001 in words is "one hundred forty-four billion, three hundred thirty-two million, one hundred twenty thousand, one".
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