Base | Representation |
---|---|
bin | 11010111000101000… |
… | …01100110111100001 |
3 | 1101020220112222222022 |
4 | 31130110030313201 |
5 | 214030011420340 |
6 | 10344124151225 |
7 | 1020452302640 |
oct | 153424146741 |
9 | 41226488868 |
10 | 14433701345 |
11 | 61374a24a8 |
12 | 2969998515 |
13 | 14904200ab |
14 | 9acd31357 |
15 | 5972523b5 |
hex | 35c50cde1 |
14433701345 has 16 divisors (see below), whose sum is σ = 19916238720. Its totient is φ = 9836671104.
The previous prime is 14433701341. The next prime is 14433701351. The reversal of 14433701345 is 54310733441.
14433701345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 14433701345 - 22 = 14433701341 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is not an unprimeable number, because it can be changed into a prime (14433701341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1259300 + ... + 1270709.
It is an arithmetic number, because the mean of its divisors is an integer number (1244764920).
Almost surely, 214433701345 is an apocalyptic number.
It is an amenable number.
14433701345 is a deficient number, since it is larger than the sum of its proper divisors (5482537375).
14433701345 is a wasteful number, since it uses less digits than its factorization.
14433701345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2530184.
The product of its (nonzero) digits is 60480, while the sum is 35.
The spelling of 14433701345 in words is "fourteen billion, four hundred thirty-three million, seven hundred one thousand, three hundred forty-five".
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