Base | Representation |
---|---|
bin | 1000011001101110000… |
… | …1011001011111010011 |
3 | 111210120112002110211022 |
4 | 2012123201121133103 |
5 | 4331103321110103 |
6 | 150151010310055 |
7 | 13266646324613 |
oct | 2063341313723 |
9 | 453515073738 |
10 | 144343144403 |
11 | 56240a3a887 |
12 | 23b8428832b |
13 | 107c4609323 |
14 | 6db4386a43 |
15 | 3b4c179138 |
hex | 219b8597d3 |
144343144403 has 4 divisors (see below), whose sum is σ = 149320494240. Its totient is φ = 139365794568.
The previous prime is 144343144397. The next prime is 144343144411. The reversal of 144343144403 is 304441343441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 144343144403 - 224 = 144326367187 is a prime.
It is a super-2 number, since 2×1443431444032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (144343144483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2488674875 + ... + 2488674932.
It is an arithmetic number, because the mean of its divisors is an integer number (37330123560).
Almost surely, 2144343144403 is an apocalyptic number.
144343144403 is a deficient number, since it is larger than the sum of its proper divisors (4977349837).
144343144403 is an equidigital number, since it uses as much as digits as its factorization.
144343144403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4977349836.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 144343144403 its reverse (304441343441), we get a palindrome (448784487844).
The spelling of 144343144403 in words is "one hundred forty-four billion, three hundred forty-three million, one hundred forty-four thousand, four hundred three".
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