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144411323233 = 469130784763
BaseRepresentation
bin1000011001111110010…
…1011110101101100001
3111210202021101022121011
42012133211132231201
54331223244320413
6150201443500521
713301434664662
oct2063745365541
9453667338534
10144411323233
1156276477621
1223ba3087741
131080578ac28
146dbd453369
153b5314533d
hex219f95eb61

144411323233 has 4 divisors (see below), whose sum is σ = 144442112688. Its totient is φ = 144380533780.

The previous prime is 144411323227. The next prime is 144411323293. The reversal of 144411323233 is 332323114441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144411323233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144411323195 and 144411323204.

It is not an unprimeable number, because it can be changed into a prime (144411323213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15387691 + ... + 15397072.

It is an arithmetic number, because the mean of its divisors is an integer number (36110528172).

Almost surely, 2144411323233 is an apocalyptic number.

It is an amenable number.

144411323233 is a deficient number, since it is larger than the sum of its proper divisors (30789455).

144411323233 is an equidigital number, since it uses as much as digits as its factorization.

144411323233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30789454.

The product of its digits is 20736, while the sum is 31.

Adding to 144411323233 its reverse (332323114441), we get a palindrome (476734437674).

The spelling of 144411323233 in words is "one hundred forty-four billion, four hundred eleven million, three hundred twenty-three thousand, two hundred thirty-three".

Divisors: 1 4691 30784763 144411323233