144411421341203 has 4 divisors (see below), whose sum is σ = 152906210831880. Its totient is φ = 135916631850528.

The previous prime is 144411421341151. The next prime is 144411421341227. The reversal of 144411421341203 is 302143124114441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144411421341203 - 2⁸ = 144411421340947 is a prime.

It is a super-2 number, since 2×144411421341203² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144411421941203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4247394745313 + ... + 4247394745346.

It is an arithmetic number, because the mean of its divisors is an integer number (38226552707970).

Almost surely, 2^{144411421341203} is an apocalyptic number.

144411421341203 is a deficient number, since it is larger than the sum of its proper divisors (8494789490677).

144411421341203 is an equidigital number, since it uses as much as digits as its factorization.

144411421341203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8494789490676.

The product of its (nonzero) digits is 36864, while the sum is 35.

Adding to 144411421341203 its reverse (302143124114441), we get a palindrome (446554545455644).

The spelling of 144411421341203 in words is "one hundred forty-four trillion, four hundred eleven billion, four hundred twenty-one million, three hundred forty-one thousand, two hundred three".