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144412132001 = 314658455871
BaseRepresentation
bin1000011001111110100…
…0100100001010100001
3111210202022220102000112
42012133220210022201
54331224001211001
6150201513101105
713301444603624
oct2063750441241
9453668812015
10144412132001
115627697a225
1223ba33b7795
13108059b20a7
146dbd5c3dbb
153b53254cbb
hex219fa242a1

144412132001 has 4 divisors (see below), whose sum is σ = 149070587904. Its totient is φ = 139753676100.

The previous prime is 144412131953. The next prime is 144412132003. The reversal of 144412132001 is 100231214441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 144412132001 - 222 = 144407937697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144412132003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2329227905 + ... + 2329227966.

It is an arithmetic number, because the mean of its divisors is an integer number (37267646976).

Almost surely, 2144412132001 is an apocalyptic number.

It is an amenable number.

144412132001 is a deficient number, since it is larger than the sum of its proper divisors (4658455903).

144412132001 is an equidigital number, since it uses as much as digits as its factorization.

144412132001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4658455902.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 144412132001 its reverse (100231214441), we get a palindrome (244643346442).

The spelling of 144412132001 in words is "one hundred forty-four billion, four hundred twelve million, one hundred thirty-two thousand, one".

Divisors: 1 31 4658455871 144412132001