144443042113 has 4 divisors (see below), whose sum is σ = 144443806768. Its totient is φ = 144442277460.

The previous prime is 144443042077. The next prime is 144443042257. The reversal of 144443042113 is 311240344441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 144443042113 - 2⁹ = 144443041601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144443052113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128758 + ... + 552688.

It is an arithmetic number, because the mean of its divisors is an integer number (36110951692).

Almost surely, 2^144443042113 is an apocalyptic number.

It is an amenable number.

144443042113 is a deficient number, since it is larger than the sum of its proper divisors (764655).

144443042113 is an equidigital number, since it uses as much as digits as its factorization.

144443042113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 764654.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 144443042113 its reverse (311240344441), we get a palindrome (455683386554).

The spelling of 144443042113 in words is "one hundred forty-four billion, four hundred forty-three million, forty-two thousand, one hundred thirteen".