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14451114403 = 111313737673
BaseRepresentation
bin11010111010101101…
…01000000110100011
31101022010022200012101
431131112220012203
5214043441130103
610345545311231
71021053305605
oct153526500643
941263280171
1014451114403
116146306160
122973795517
131493c08b8b
149b1385175
15598a41a1d
hex35d5a81a3

14451114403 has 4 divisors (see below), whose sum is σ = 15764852088. Its totient is φ = 13137376720.

The previous prime is 14451114347. The next prime is 14451114409. The reversal of 14451114403 is 30441115441.

14451114403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14451114403 - 213 = 14451106211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14451114409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 656868826 + ... + 656868847.

It is an arithmetic number, because the mean of its divisors is an integer number (3941213022).

Almost surely, 214451114403 is an apocalyptic number.

14451114403 is a deficient number, since it is larger than the sum of its proper divisors (1313737685).

14451114403 is a wasteful number, since it uses less digits than its factorization.

14451114403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1313737684.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 14451114403 its reverse (30441115441), we get a palindrome (44892229844).

The spelling of 14451114403 in words is "fourteen billion, four hundred fifty-one million, one hundred fourteen thousand, four hundred three".

Divisors: 1 11 1313737673 14451114403