14476797113 has 4 divisors (see below), whose sum is σ = 14478044160. Its totient is φ = 14475550068.

The previous prime is 14476797079. The next prime is 14476797161. The reversal of 14476797113 is 31179767441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31179767441 = 547 ⋅57001403.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14476797113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14476797173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605945 + ... + 629382.

It is an arithmetic number, because the mean of its divisors is an integer number (3619511040).

Almost surely, 2^14476797113 is an apocalyptic number.

It is an amenable number.

14476797113 is a deficient number, since it is larger than the sum of its proper divisors (1247047).

14476797113 is a wasteful number, since it uses less digits than its factorization.

14476797113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1247046.

The product of its digits is 889056, while the sum is 50.

The spelling of 14476797113 in words is "fourteen billion, four hundred seventy-six million, seven hundred ninety-seven thousand, one hundred thirteen".