Base | Representation |
---|---|
bin | 1101001011100010110111… |
… | …0110101010011111010011 |
3 | 1220022102100121221201202121 |
4 | 3102320231312222133103 |
5 | 3344414043133224420 |
6 | 50453310001555111 |
7 | 3024003665462662 |
oct | 322705566523723 |
9 | 56272317851677 |
10 | 14491988961235 |
11 | 4688021a66095 |
12 | 1760789945a97 |
13 | 8117864952a6 |
14 | 3815b7752dd9 |
15 | 1a1e835a52aa |
hex | d2e2ddaa7d3 |
14491988961235 has 16 divisors (see below), whose sum is σ = 17650569506976. Its totient is φ = 11420148250368.
The previous prime is 14491988961199. The next prime is 14491988961253. The reversal of 14491988961235 is 53216988919441.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14491988961235 is a prime.
It is a super-3 number, since 3×144919889612353 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8894437 + ... + 10396873.
It is an arithmetic number, because the mean of its divisors is an integer number (1103160594186).
Almost surely, 214491988961235 is an apocalyptic number.
14491988961235 is a deficient number, since it is larger than the sum of its proper divisors (3158580545741).
14491988961235 is a wasteful number, since it uses less digits than its factorization.
14491988961235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1531302.
The product of its digits is 134369280, while the sum is 70.
The spelling of 14491988961235 in words is "fourteen trillion, four hundred ninety-one billion, nine hundred eighty-eight million, nine hundred sixty-one thousand, two hundred thirty-five".
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