Base | Representation |
---|---|
bin | 11011000000010110… |
… | …01011001101101011 |
3 | 1101102102101021101120 |
4 | 31200023023031223 |
5 | 214143100203024 |
6 | 10354355550323 |
7 | 1022166512304 |
oct | 154013131553 |
9 | 41372337346 |
10 | 14498444139 |
11 | 616aaa2743 |
12 | 29875bb3a3 |
13 | 14a096aa3a |
14 | 9b77857ab |
15 | 59cc90479 |
hex | 3602cb36b |
14498444139 has 4 divisors (see below), whose sum is σ = 19331258856. Its totient is φ = 9665629424.
The previous prime is 14498444137. The next prime is 14498444153. The reversal of 14498444139 is 93144489441.
14498444139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14498444139 - 21 = 14498444137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14498444091 and 14498444100.
It is not an unprimeable number, because it can be changed into a prime (14498444131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2416407354 + ... + 2416407359.
It is an arithmetic number, because the mean of its divisors is an integer number (4832814714).
Almost surely, 214498444139 is an apocalyptic number.
14498444139 is a deficient number, since it is larger than the sum of its proper divisors (4832814717).
14498444139 is an equidigital number, since it uses as much as digits as its factorization.
14498444139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4832814716.
The product of its digits is 1990656, while the sum is 51.
The spelling of 14498444139 in words is "fourteen billion, four hundred ninety-eight million, four hundred forty-four thousand, one hundred thirty-nine".
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